(7x+5)(3x^2-11x-4)=0

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Solution for (7x+5)(3x^2-11x-4)=0 equation: 


Simplifying
(7x + 5)(3x2 + -11x + -4) = 0

Reorder the terms:
(5 + 7x)(3x2 + -11x + -4) = 0

Reorder the terms:
(5 + 7x)(-4 + -11x + 3x2) = 0

Multiply (5 + 7x) * (-4 + -11x + 3x2)
(5(-4 + -11x + 3x2) + 7x * (-4 + -11x + 3x2)) = 0
((-4 * 5 + -11x * 5 + 3x2 * 5) + 7x * (-4 + -11x + 3x2)) = 0
((-20 + -55x + 15x2) + 7x * (-4 + -11x + 3x2)) = 0
(-20 + -55x + 15x2 + (-4 * 7x + -11x * 7x + 3x2 * 7x)) = 0
(-20 + -55x + 15x2 + (-28x + -77x2 + 21x3)) = 0

Reorder the terms:
(-20 + -55x + -28x + 15x2 + -77x2 + 21x3) = 0

Combine like terms: -55x + -28x = -83x
(-20 + -83x + 15x2 + -77x2 + 21x3) = 0

Combine like terms: 15x2 + -77x2 = -62x2
(-20 + -83x + -62x2 + 21x3) = 0

Solving
-20 + -83x + -62x2 + 21x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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